Could you please explain a bit more about how p values are calculated for the AMOVA test?
I have a dataset with 2 groups of 5 replicates each. This is 10!/2!(5!)^2 or 126 ways to make 2 groups of 5 where order does not matter. So, I am trying to understand how I can get a p-value that is <0.001? It seems like the lowest possible p value should be 1/126 or 0.008. When the row/column names of the distance matrix are shuffled, does order matter?
Thanks very much for your help!